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JEE MAIN - Physics (2025 - 3rd April Morning Shift - No. 4)

The angle of projection of a particle is measured from the vertical axis as $\phi$ and the maximum height reached by the particle is $\mathrm{h}_{\mathrm{m}}$. Here $\mathrm{h}_{\mathrm{m}}$ as function of $\phi$ can be presented as
JEE Main 2025 (Online) 3rd April Morning Shift Physics - Motion in a Plane Question 2 English Option 1
JEE Main 2025 (Online) 3rd April Morning Shift Physics - Motion in a Plane Question 2 English Option 2
JEE Main 2025 (Online) 3rd April Morning Shift Physics - Motion in a Plane Question 2 English Option 3
JEE Main 2025 (Online) 3rd April Morning Shift Physics - Motion in a Plane Question 2 English Option 4

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JEE Main 2025 (Online) 3rd April Morning Shift Physics - Motion in a Plane Question 2 English Explanation

$\mathrm{H}_{\max }=\frac{\mathrm{u}^2 \cos ^2 \phi}{2 \mathrm{~g}}$

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